C Program for whether inputed number is an armstrong number or not by using while loop

 Armstrong Number

It is a magical number that is equal to the sum of cubes of its digits. For example 0, 1, 153, 370, 371 and 407 are the Armstrong numbers.

153 = (1x1x1)+(5x5x5)+(3x3x3)  

where:  

(1x1x1)=1  

(5x5x5)=125  

(3x3x3)=27  

So:  

1+125+27=153

C Program

//C Program to input a number and

//check whether armstrong number or not

#include<stdio.h>

#include<conio.h>

void main()

{

clrscr();

int n, temp=0, r, sum=0;

printf("Enter a number\n");

scanf("%d",&n);

temp=n;

while(n>0)

{

r = n % 10;

sum = sum + (r*r*r);

n = n / 10;

}

if(sum == temp)

printf("%d is an armstrong number",temp);

else

printf("%d is not an armstrong number",temp);

getch();

}

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